3(x^2-4)=2x^2+3

Solution for 3(x^2-4)=2x^2+3 equation:

Simplifying
3(x2 + -4) = 2x2 + 3

Reorder the terms:
3(-4 + x2) = 2x2 + 3
(-4 * 3 + x2 * 3) = 2x2 + 3
(-12 + 3x2) = 2x2 + 3

Reorder the terms:
-12 + 3x2 = 3 + 2x2

Solving
-12 + 3x2 = 3 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
-12 + 3x2 + -2x2 = 3 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
-12 + 1x2 = 3 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-12 + 1x2 = 3 + 0
-12 + 1x2 = 3

Add '12' to each side of the equation.
-12 + 12 + 1x2 = 3 + 12

Combine like terms: -12 + 12 = 0
0 + 1x2 = 3 + 12
1x2 = 3 + 12

Combine like terms: 3 + 12 = 15
1x2 = 15

Divide each side by '1'.
x2 = 15

Simplifying
x2 = 15

Take the square root of each side:
x = {-3.872983346, 3.872983346}